Answer:
(x-2)
Step-by-step explanation:
Given expression is [tex]\frac{(x+1)^2-9}{x+4}[/tex]
Now we factor the given expression
LEts factor the numerator
(x+1)^2 -9
9 can be written as 3^2
(x+1)^2 - 3^2
Now we apply a^2 - b^2 formula
a^2 - b^2 = (a+b)(a-b)
(x+1)^2 - 3^2 = (x+1+3)(x+1-3)=(x+4)(x-2)
now we replace it in our problem
[tex]\frac{(x+1)^2-9}{x+4}=\frac{(x+4)(x-2)}{x+4}[/tex]
Cancel out x+4 from top and bottom
So answer is (x-2)