Question

What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K? Use mc031-1.jpg and mc031-2.jpg. 0.715 kPa 2.45 kPa 28.2 kPa 62.7 kPa

Answer 1

The answer for this question is 28.2kPa hope im not incorrect about this one

Answer 2

Given information:

Number of Moles of the ideal gas, n = 0.540

Volume, V = 35.5 L

Temperature, T = 223 K

To determine:

Pressure, P of the ideal gas under the given conditions

Explanation:

The ideal gas equation relates state parameters like P, V and T through the relation:

PV = nRT

here R is the gas constant = 8.314 L.kPa.K⁻¹mol⁻¹

P = nRT/V

P = 0.540 mol * 8.314 L.kPa.K⁻¹mol⁻¹*223 K/35.5 L = 28.2 kPa

Ans: The pressure of the ideal gas under the given conditions is 28.2 kPa