A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The calorimeter and the water have a combined mass of 250.0 g and an overall specific heat of 1.035 cal/g•°C. The initial temperature of the calorimeter is 10.00°C. The system reaches a final temperature of 11.08°C when the metal is added.

Respuesta :

First, in order to calculate the specific heat capacity of the metal in help in identifying it, we must find the heat absorbed by the calorimeter using:
Energy = mass * specific heat capacity * change in temperature
Q = 250 * 1.035 * (11.08 - 10)
Q = 279.45 cal/g

Next, we use the same formula for the metal as the heat absorbed by the calorimeter is equal to the heal released by the metal.

-279.45 = 50 * c * (11.08 - 45) [minus sign added as energy released]
c = 0.165

The specific heat capacity of the metal is 0.165 cal/gC

The specific heat capacity of the unknown metal has been 0.164 cal/g.[tex]\rm ^\circ C[/tex].

Specific heat can be defined as the amount of energy required to raise the temperature of 1 gram of a substance by 1 degree celsius.

The expression can be given as:

heat = mass [tex]\times[/tex] specific heat capacity [tex]\times[/tex] change in temperature

The heat absorbed by Calorimeter can be given as:

Heat absorbed = 250 grams [tex]\times[/tex] 1.035 cal/g.[tex]\rm ^\circ C[/tex] [tex]\times[/tex] (11.08 [tex]\rm ^\circ C[/tex] - 10.00[tex]\rm ^\circ C[/tex] )

Heat absorbed by calorimeter = 250 [tex]\times[/tex] 1.035 [tex]\times[/tex] 1.08

Heat absorbed by calorimeter = 279.45 cal

The heat absorbed by calorimeter has been equal to the heat released by metal.

Heat released by metal = 279.45 cal

Heat released = mass [tex]\times[/tex] specific heat capacity [tex]\times[/tex] change in temperature

279.45 cal = 50 g [tex]\times[/tex] specific heat capacity [tex]\times[/tex] (11.08 [tex]\rm ^\circ C[/tex] - 45.0 [tex]\rm ^\circ C[/tex] )

279.45 = 50 [tex]\times[/tex] specific heat capacity [tex]\times[/tex] -33.92

Specific heat capacity = 0.164 cal/g.[tex]\rm ^\circ C[/tex].

The specific heat capacity of the unknown metal has been 0.164 cal/g.[tex]\rm ^\circ C[/tex].

For more information about the specific heat capacity, refer to the link:

https://brainly.com/question/11194034

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