Question

A 6.00 liter sample of air has a pressure of 207 kilopascals at a temperature of 50°C. Which law will you use to calculate the new pressure if the temperature is raised to 202°C, and the volume expands to 9.0 liters?

Answer 1

Ideal gas law is your answer

Answer 2

Ideal gas law is used for the calculation.

According to the ideal gas law:

PV = nRT

Calculation

Given P₁ = 207 kPa                                  P₂ = ? = P (Let it be)

          V₁ = 6 L                                          V₂ = 9 L

          T₁ = 50° C = 323 K                         T₂ = 202° C = 475 K

P₁V₁/nRT₁ = P₂V₂/nRT₂

Putting the values in the above equation, we get

$\frac{207(6)}{nR (323)} = \frac{P (9)}{nR(475)}$

$P = \frac{207(6)(475)}{323(9)}$

P = P₂  = 203 kPa

Learn more about ideal gas law here:

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