willpoyner willpoyner
  • 19-06-2017
  • Mathematics
contestada

solve for a 1/a + 1/2a = 1/a-3
a=3
a=-3
a=9
a=-9

Respuesta :

Аноним Аноним
  • 20-06-2017
D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

(1/2)*a+1/a = 1/a-3 // - 1/a-3

(1/2)*a+1/a-(1/a)+3 = 0

(1/2)*a+1/a-a^-1+3 = 0

1/2*a+3 = 0 // - 3

1/2*a = -3 // : 1/2

a = -3/1/2

a = -6

a = -6
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