Respuesta :
The ratio of the initial kinetic energy to the final kinetic energy is 4:1
Kinetic energy (KE) is given as [tex] \frac{1}{2} mv^{2} [/tex] i.e. it is proportional to [tex] v^{2} [/tex] i.e. the square of speed.
We write the initial kinetic energy is KE.1 =(1/2)mu^2
When speed is halved, speed will be u/2,
then final kinetic energy will be KE.2 = ( 1/2)m[u/2]^2 = (1/8)mu^2
Now,ON SOLVING K,E1 /K.E2, WE GET = 4:1
Kinetic energy (KE) is given as [tex] \frac{1}{2} mv^{2} [/tex] i.e. it is proportional to [tex] v^{2} [/tex] i.e. the square of speed.
We write the initial kinetic energy is KE.1 =(1/2)mu^2
When speed is halved, speed will be u/2,
then final kinetic energy will be KE.2 = ( 1/2)m[u/2]^2 = (1/8)mu^2
Now,ON SOLVING K,E1 /K.E2, WE GET = 4:1
The ratio of the initial kinetic energy to the final kinetic energy is 4 : 1
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Further explanation
Let's recall Kinetic Energy Formula as follows:
[tex]\large {\boxed{Ek = \frac{1}{2}mv^2} }[/tex]
Ek = Kinetic Energy ( Joule )
m = mass of the object ( kg )
v = speed of the object ( m/s )
Let us now tackle the problem !
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Given:
initial speed of the object = v
final speed of the object = ¹/₂v
Asked:
ratio of kinetic energy = Ek : Ek' = ?
Solution:
[tex]Ek : Ek' = \frac{1}{2}mv^2 : \frac{1}{2}m(v')^2[/tex]
[tex]Ek : Ek' = v^2 : (v')^2[/tex]
[tex]Ek : Ek' = v^2 : (\frac{1}{2}v)^2[/tex]
[tex]Ek : Ek' = v^2 : \frac{1}{4}v^2[/tex]
[tex]Ek : Ek' = 1 : \frac{1}{4}[/tex]
[tex]Ek : Ek' = 4 : 1[/tex]
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Learn more
- Impacts of Gravity : https://brainly.com/question/5330244
- Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454
- The Acceleration Due To Gravity : https://brainly.com/question/4189441
- Newton's Law of Motion: https://brainly.com/question/10431582
- Example of Newton's Law: https://brainly.com/question/498822
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Answer details
Grade: High School
Subject: Physics
Chapter: Dynamics
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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant , Wall
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