In a parallel connection, the voltage is same in every branch.
Now, three three resistors connected in parallel.
R1 = 2k ohm
R2 = 6k ohm
R3 = 10k ohm
in parallel, net resisitance = [tex] \frac{ R_{1}R_{2}R_{3} }{R_{1}R_{2} + R_{2}R_{3} + R_{3}R_{1}} [/tex]
Now, putting the values, we get, R net = 1.30 k ohm.
Ans, voltage = 100 VDC
Thus, power = [tex] \frac{ V^{2} }{R} = \frac{ 100^{2} }{1.3 k} \\ \\ where \\ k = 10^{3}
[/tex]
= 7.69 Watt
