Respuesta :

2C₄H₁₀ + 13O₂ = 8CO₂ + 10H₂O

C₄H₁₀→5H₂→2.5O₂→2C₄H₁₀→5O₂
8C→8O₂
5+8=13O₂

At combustion of butane the carbon dioxide and water are formed.
The carbon dioxide and water is products of the complete combustion of hydrocarbons.

Answer:

The products of methane combustion (C4H10) are carbon dioxide (CO2) and water (H2O). 2 moles of methane are burned with 13 moles of oxygen to produce 8 moles of carbon dioxide and 10 moles of water. The adjusted reaction is as follows:

2C4H10 + 13O2 = 8CO2 + 10H2O

Reaction Type: Combustion

Explanation:

In the combustion of methane there are a series of stages: first, methane reacts with oxygen and forms formaldehyde. It decomposes forming the formyl radical, and then carbon monoxide and hydrogen are produced, in a process known as oxidative pyrolysis. Following this process, hydrogen is oxidized and water is produced, with a release of heat. As a last step, carbon monoxide oxidizes to form carbon dioxide with another heat release.