Question

Find ∆G for a cell whose potential is +0.24 V with 4 moles of electrons exchanged.

Answer 1

we need to use the following formula
Δ$G= -nF E_{cell}$

$E_{cell}= 0.24V$
n= 4 moles
F= constant= 96500C/mol

let's plug in the values.

ΔG= -(4)(96500)(0.24)= -92640 J or -92.6 kJ

Answer 2

Step 1.  Use  ∆G = -nFEo.

Step 2.  Plug in n = 4, F = 96,500 and E = +0.24

Step 3.   ∆G = -4 × 96,500 × 0.24    =   -92,640 J   =   -92.64 kJ.