Respuesta :
Over here you have to use the formula: P1/T1= P2/T2
P1= 7.58
T1= 639
P2= ?
T2= 311
7.58/639 = ?/311
= 3.689 kPa
P1= 7.58
T1= 639
P2= ?
T2= 311
7.58/639 = ?/311
= 3.689 kPa
Answer: 3.69 kPa
Explanation:
Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.
[tex]P\propto T[/tex] (At constant volume and number of moles)
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 7.58 kPa
[tex]P_2[/tex] = final pressure of gas = ?
[tex]T_1[/tex] = initial temperature of gas = 639 K
[tex]T_2[/tex] = final temperature of gas = 311 K
Now put all the given values in the above equation, we get the final pressure of gas.
[tex]\frac{7.58 kPa}{639K}=\frac{P_2}{311K}[/tex]
[tex]P_2=3.69kPa[/tex]
Therefore, the final pressure of gas will be 3.69 kPa.