Respuesta :

tonb
This polynomial has no real roots, since its discriminant < 0. This can be calculated as b^2-4ac = 9-4*5 = -11.


If you allow complex roots, they are:

[tex]x = - \frac12 i (\sqrt{11} - 3i)[/tex]

and

[tex]x = \frac12 i (\sqrt{11} + 3i)[/tex]
ACCESS MORE
EDU ACCESS