you didn't give us any but we can still solve
so get into y=mx+b form
ignore the inequality sign (flip if you mutiply or divide bya negat0ve)
6x+3y≤12
minus 6x
3y≤-6x+12
divide 3
y≤-2x+4
y≤-2x+4
graph y=-2x+4, draw with solid line since we have ≤ and not <
now pick a point on any side to see if it satisfies
hmm, is (0,0) in the solution set?
0≤-2(0)+4
0≤4
false
so (0,0) Is not in the shaded area
graph y=-2x+4 and shade above the line (or to the right)
