Question

what is the value of x in the equation (1/4)x^4-x^2=(5/4)

Answer 1

(1/2)x^2 = T

T^2 - 2T - 5/4 = 0
4T^2 - 8T - 5 = 0
(2T-5)(2T+1) = 0
T = 5/2 >>> (1/2)x^2 = 5/2
x = root(5)
x = -root (5)
T = -1/2 >>> no root (1/2x^2 = pozitive)


Good Luck :D