Respuesta :
y = 2x + 1
y = x²+1
reemplazando
2x+1 = x²+1
ordenando
0=x²-2x
donde
0 = x (x-2)
resolviendo
0=x v x-2=0
0 =x x= 2
si x=0 entonces y = 1 par (0,1)
si x=2 entonces y= 5 par (2,5)
respuesta A
y = x²+1
reemplazando
2x+1 = x²+1
ordenando
0=x²-2x
donde
0 = x (x-2)
resolviendo
0=x v x-2=0
0 =x x= 2
si x=0 entonces y = 1 par (0,1)
si x=2 entonces y= 5 par (2,5)
respuesta A
1) The ordered pairs [tex](0, 1)[/tex] and [tex](2,5)[/tex] are solutions of the system.
2) The product of [tex]\frac{1}{2}\cdot x - \frac{1}{4}[/tex] and [tex]5\cdot x^{2}-2\cdot x + 6[/tex] is [tex]\frac{5}{2}\cdot x^{5}-\frac{5}{4}\cdot x^{4}-x^{2}+\frac{7}{2}\cdot x-\frac{3}{2}[/tex].
How to solve a system of two polynomic equations
1) In this question, we must solve for [tex]x[/tex] and [tex]y[/tex] the following system of equations:
[tex]y = 2\cdot x + 1[/tex] (1)
[tex]y=x^{2}+1[/tex] (2)
By (1) and (2):
[tex]2\cdot x + 1 = x^{2}+1[/tex]
[tex]x^{2}-2\cdot x = 0[/tex]
[tex]x\cdot (x-2) = 0[/tex]
The solutions for [tex]x[/tex] are 0 and 2, respectively.
Lastly, we find the solutions for [tex]y[/tex] by (1):
x = 0
[tex]y = 2\cdot 0 + 1[/tex]
[tex]y = 1[/tex]
x = 2
[tex]y = 2\cdot 2 +1[/tex]
[tex]y = 5[/tex]
The solutions for [tex]y[/tex] are 1 and 5, respectively.
The ordered pairs [tex](0, 1)[/tex] and [tex](2,5)[/tex] are solutions of the system. [tex]\blacksquare[/tex]
How to find resulting polynomial by operations between polynomials
2) In this case, we must determine the product of two polynomials by algebraic means:
- [tex]\left(\frac{1}{2}\cdot x-\frac{1}{4} \right)\cdot (5\cdot x^{2}-2\cdot x + 6)[/tex] Given
- [tex]\left(\frac{1}{2}\cdot x - \frac{1}{4} \right)\cdot (5\cdot x^{4})+\left(\frac{1}{2}\cdot x - \frac{1}{4} \right)\cdot (-2\cdot x)+\left(\frac{1}{2}\cdot x - \frac{1}{4} \right)\cdot (6)[/tex] Distributive property
- [tex]\left(\frac{5}{2}\cdot x^{5}-\frac{5}{4}\cdot x^{4}\right)+\left(-x^{2}+\frac{1}{2}\cdot x \right)+\left(3\cdot x-\frac{3}{2} \right)[/tex] Distributive property/[tex]x^{m}\cdot x^{n} = x^{m+n}[/tex]
- [tex]\frac{5}{2}\cdot x^{5}-\frac{5}{4}\cdot x^{4}-x^{2}+\frac{7}{2}\cdot x-\frac{3}{2}[/tex] Associative, distributive and commutative properties/Result
The product of [tex]\frac{1}{2}\cdot x - \frac{1}{4}[/tex] and [tex]5\cdot x^{2}-2\cdot x + 6[/tex] is [tex]\frac{5}{2}\cdot x^{5}-\frac{5}{4}\cdot x^{4}-x^{2}+\frac{7}{2}\cdot x-\frac{3}{2}[/tex]. [tex]\blacksquare[/tex]
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