Question

A 30.5 gram sample of glucose (C6H12O6) contains __________ atoms of carbon.

Answer 1

Before we get into the calculation, there are several things that we need to pay attention to:
- There are 6 moles of C
- The carbon mass of a glucose is 180.15 g

So,

#30.5g Glucose(1 mol of glucose/180.15g Glucose)=.169 mol glucose
#169 mol glucose(6 Moles of C/1mol C6H12O6)    =1.014 mol of C 
#1.014 Mol C(6.022x10^23 atoms/ 1 Mol)                 = 6.11 X 10^23 Atoms of C