solve for the value of x such that f(x)=8
imma assume it is y=x^(3/2)
so
solve 8=x^(3/2)
x=4
so integrate from x=0 to x=4
[tex]\pi \int\limits^4_0 {(x^ \frac{3}{2})^2 } \, dx [/tex] is the area
[tex]\pi \int\limits^4_0 {x^3 } \, dx [/tex]=
[tex]\pi [ \frac{1}{4}x^4 ]^4_0[/tex]=
[tex]\pi (4^3)[/tex]=
64π cubic units