To calculate the temperature of the log we need the Stefan-Boltzmann's law:
P=A*ε*σ*T⁴, where P is the power emitted by the body,
A is the total surface area of the body, in our case it is a cylinder so A=r²π*h where r is the radius of the base of the cylinder and h is the height of the cylinder,
σ is the Stefan-Boltzmann constant, T is temperature and ε is emissivity .
Here we are approximating the log to be a black body.
The area of the cylinder:
A=r²*π*h, r=d/2=0.75/2=0.375 m, where d is the diameter, h=0.18 m
A=0.07948 m²
Lets solve the equation for temperature T:
T⁴=P/(σ*ε*A) and take the 4th root to get T:
T=⁴√{P/(σ*ε*A)}=⁴√{38000/((5.67*10^-8)*1*0.07948)} = ⁴√(8.432*10^12)= 1704.06 C
So the temperature of the log is T= 1704 C
