Respuesta :

the answer is c <GDH and <EDH because they are congruent to each other and i just took the test. :)

we know that

m∠EDF=[tex] m\ arc \ EF=115 [/tex]°------> by central angles

m∠FDG=[tex] m\ arc \ FG=115 [/tex]°------> by central angles

m∠EDH=[tex] m\ arc \ HE=65 [/tex]°------> by central angles

m∠GDH=[tex] m\ arc \ HG=65 [/tex]°------> by central angles

so

The congruent angles are

m∠EDF=m∠FDG

m∠EDH=m∠GDH

therefore

the answer is

m∠EDH=m∠GDH


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