Question

What is the number of moles of gas contained in a 3 L vessel at 300 K with a pressure of 1.50 atm? (Given: R = 0.08205 L∙atm/mol∙K) 4.5 mol 0.18 mol 24.63 mol 5.47 mol 1.8 mol

Answer 1

P= 1.50 atm
V= 3 L
R= 0.08205 L∙atm/mol∙K
T= 300 K
n= ?

we all this information, we can tell that we need to use ideal gas formula

PV= nRT

if we rearrange the formula for n, we get--> n= PV/ RT

let's plug in the values. 

n= 1.5 x 3/ (0.08205 x 300)= 0.18 moles

Answer 2

The ideal gas law states the relation between pressure, volume, moles and the temperature of the ideal gas. The number of moles present in the container is 0.18 moles.

What is ideal gas law?

According to the ideal gas law the proportionality relation between the pressure, volume, moles and the temperature of the hypothetical gas is given. The formula for the ideal gas equation is,

$\rm PV = nRT$

Where,

Pressure (P) = 1.50 atm

Volume (V) = 3 L

Temperature (T) = 300 K

Gas constant (R) = 0.08205

Number of moles = n

Substituting values in the ideal gas equation:

$\begin{aligned} \rm n &= \rm \dfrac{PV}{RT}\\\\&= \dfrac{1.50 \times 3}{300 \times 0.08205}\\\\&= 0.18 \;\rm moles\end{aligned}$

Therefore, option B. 0.18 moles of gas is contained in the vessel.

Learn more about ideal gas here:

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