Question

1/3 of Murka’s age is twice as much as Ivan’s age. What is the ratio of Murka’s age to Ivan’s age?

Answer 1

Let these two ages be i and m.  Then (1/3)m = 2i, which becomes m = 6i when we multiply both sides by 3.

Ratio:

M's age      6i
---------- = ------ = 6
I's age         i

M is 6 times older than Ivan.

The ratio of M's age to Ivan's is 6:1, or just 6.

Answer 2

1/3 of Murka’s age is twice as much as Ivan’s age. The ratio of Murka’s age to Ivan’s age is 6:1, or just 6.

What is a linear equation?

A linear equation is an equation that has the variable of the highest power of 1. The standard form of a linear equation is of the form Ax + B = 0.

1/3 of Murka’s age is twice as much as Ivan’s age.

Let the two ages be x and y.  

Then (1/3)y = 2x, which becomes y = 6x when we multiply both sides by 3.

Ratio

Murka’s age/ Ivan’s age = 6x/x

= 6

Murka is 6 times older than Ivan.

thus, The ratio of Murka’s age to Ivan’s age is 6:1, or just 6.

Learn more about linear equations;

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