The diameter of a circle has endpoints P(-7,-10) and q(3,2)
A find the center of the circle
B find the radius. If it's not an integer express it in radical form
C write an equation for the circle

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Respuesta :

A. The center of the circle is the midpoint of the given endpoints. That is,
                             x-coordinate = (-7 + 3) / 2 = -2
                             y-coordinate = (-10 + 2) = -4
The coordinates are (-2,-4)

B. The radius of the circle is the distance between the center and one of the points. 
                                r = sqrt ((-10 - -2)^2 + ( -7 - -4)^2) = sqrt of 73

C. The equation of the circle is written through the equation,
                                    (x - -2)^2 + (y - -4)^2 = (sqrt of 73)^2
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