Respuesta :

the change in boiling point =kb×m
kb is the boiling constant of the solvent
m is the molality of the solute

kb= 0.512
m= moles of solute/mass of solvent( in Kg)

moles =mass/molar mass
molar mass of the acid = 10×C +8×H +6×O +2×S =10×12 + 8×1 +6×16 +2×32 = 288

moles of the acid =1×10^2/288= 0.35 moles

mass of water= 1×10^2g ×(1kg/1000g) = 0.1kg

m=0.35/0.1 = 3.5 mol/Kg

change in boiling = 0.512×3.5 = 1.792

new boiling point = 100+1.792 = 101.792 degrees
to find the boiling point (bp) of a solution, use the following formula:

bp solution= bp solvent + Δbp solution

bp solvent is known because we know the solvent is water and the boiling point of water is 100 °C

to find the elevation in boiling point, Δbp solution, we use the following formula

Δbp solution= Kb x i x m, where Kb is the boiling point constant, i is the number of particles, and m is molality. 

Kb= 0.512
i= 1, because they told you that the solute is nonionizing.
m= ?, we need to find

molality (m)= moles/ Kg solvent

to find the moles, we can use the grams of the solvent and convert it to moles using the molar mass of the molecule. 

molar mass of C10H8O6S2= 288.1 g/mol

1.00 x 10^2 g (1 mol/ 288.1 g)= 0.347 moles

the solvent is H2O,    ---> 1.00 x 10^2 g= 0100 Kg water (just divide by 1000)

molality= 0.347 moles/ 0.100 Kg= 3.47 m

now that we have molality, m, we can plug it in the Δbp solution formula

Δbp solution= Kb x i x m

Δbp solution= (0.512) x (1) x(3.47)= 1.78 °C

finally, we can solve for the boiling point

bp solution= bp solvent + Δbp solution

bp solution= 100°C + 1.78°C= 101.78°C

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