Question

What are the solutions to the systems?

y=x^2-4x-2
y=x-2

Answer 1

y=x^2-4x-2
y=x-2

$x^2-4x-2=x-2\\\\x^2-4x-2-x+2=0\\\\x^2-5x=0\\\\x(x-5)=0\\\\x=0 \ or \  x-5=0$

x=0 or x=5 

y = x - 2
1)
x=0
y = 0 - 2= -2
2)
x=5
y=5-2=3

Answer
x=0 , y=-2
or
x=5 , y=3