consider the function: y=f(x)=(1/2)^x
the values of f(-7) is:
a) 0.0078
b) 0.78
c) 64
d) 128

the value of f(5) rounded to the nearest ten thousand is:
a) 0.0309
b) 0.0312
c) 0.0313
d) 32

Respuesta :

1/2^-7=128
(1/2)^5=.0313

Answer:

1. The correct option is d.

2. The correct option is c.

Step-by-step explanation:

The given function is

[tex]f(x)=(\frac{1}{2})^x[/tex]

1. To find the value of f(-7) substitute x=-7 in the given function.

[tex]f(-7)=(\frac{1}{2})^{-7}[/tex]

[tex]f(-7)=2^{7}[/tex]                         [tex][\because (\frac{1}{a})^{-n}=a^n][/tex]

[tex]f(-7)=128[/tex]

Therefore the correct option is d.

2. To find the value of f(5) substitute x=5 in the given function.

[tex]f(5)=(\frac{1}{2})^{5}[/tex]

[tex]f(5)=\frac{1}{2^5}[/tex]

[tex]f(5)=\frac{1}{32}[/tex]

[tex]f(5)=0.03125[/tex]

[tex]f(5)\approx 0.0313[/tex]

Therefore the correct option is c.