Question

In pea plants, wrinkled seeds (W) is the dominant trait, while smooth seeds (w) is the recessive trait. Consider the cross Ww X WW. What will be the ratio of wrinkled to smooth seeds? A) 0:4 wrinkled:smooth B) 2:2 wrinkled:smooth C) 3:1 wrinkled:smooth D) 4:0 wrinkled:smooth

Answer 1

To help you out, you should draw a punnet square: and as you can see, here are our results from crossing the two 

WW 
WW 
Ww 
Ww 
Since all of them have the big W (wrinkled seeds) which is the dominant trait, all of the crossed plants will be wrinkled seeds! The only way for the plants to have smooth seeds is if when we do the crossing, one of the answers is two small w's. Therefore, the answer is 4:0 (wrinkled to smooth)

Answer 2

The ratio of the wrinkled to smooth seeds will be 2:2, means 50% of the seeds will wrinkled while other 50% will be smooth.

Given here,

In a pea plant,

Wrinkled seeds (W) = dominant

Smooth seeds (w) = recessive

Cross between the Parents

Ww  x  WW

            W             W

W        WW          WW

w        Ww             Ww

Therefore, the ratio of the wrinkled to smooth seeds will be 2:2, means 50% of the seeds will wrinkled while other 50% will be smooth.

To know more about Mendel's experiment,

https://brainly.com/question/9546178