Answer : The percent composition of hydrogen in benzene is, 7.69 %
Explanation: Given,
Molar mass of C = 12 g/mole
Molar mass of H = 1 g/mole
First we have to calculate the molar mass of benzene.
Molar mass of benzene[tex](C_6H_6)[/tex] = [tex]6(12)+6(1)=78g/mole[/tex]
Now we have to calculate the percent composition of hydrogen in benzene.
As we now that there are 6 number of carbon atoms and 6 number of hydrogen atoms.
The mass of hydrogen = [tex]6\times 1=6g[/tex]
Formula used :
[tex]\%\text{ Composition of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Molar mass of hydrogen}}\times 100[/tex]
Now put all the given values in this formula, we get the percent composition of hydrogen in benzene.
[tex]\%\text{ Composition of hydrogen}=\frac{6}{78}\times 100=7.69\%[/tex]
Therefore, the percent composition of hydrogen in benzene is, 7.69 %
