Question

Does anybody know how to solve a problem like this (6x^5)^-3? I don't know where to begin.

Answer 1

remember
$(x^m)^n=x^{mn}$
and
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}= \frac{1}{x^m}$

so


$(6x^5)^{-3}=(6^{-3})((x^5)^{-3})=$
$( \frac{1}{6^5} )(x^{-15})=( \frac{1}{7776} )( \frac{1}{x^{15}})=( \frac{1}{7776x^{15}})$