Question

The two-way frequency table shows data on accidents in the last year for drivers who took a driver safety course. Given that a driver took the safety course, what is the chance that the driver still got in an accident? Round your answer to the nearest whole number.

Answer 1

Given that the driver had taken the safety course, The answer would be 22

Answer 2

Answer:

22.4%

Step-by-step explanation:

We have the events,

A = The driver got in an accident

B = The driver took the safety test

Now, it is required to find the conditional probability P(A|B).

Since, $P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}$

From the table, we have that,

$P(A\bigcap B)=28\\\\P(B)=125$

Thus, we get,

$P(A|B)=\dfrac{28}{125}$

i.e.  P(A|B) = 0.224

i.e.  P(A|B) = 22.4%

Hence, the probability that the driver got in an accident even though the driver took the safety test is 22.4%