Respuesta :
ANSWER
[tex]y = log_{12}(x) [/tex]
EXPLANATION
We want to find the inverse of the exponential function,
[tex]y = {12}^{x} [/tex]
The above function is an exponential function, so we expect the inverse to be a logarithmic function.
We now interchange x and y.
[tex]x = {12}^{y} [/tex]
We now make y the subject by taking antilogarithm of both sides to obtain,
[tex]y = log_{12}(x) [/tex]
This last function is the inverse of
.
[tex]y = 12^x[/tex]
Hence the correct answer is D
[tex]y = log_{12}(x) [/tex]
EXPLANATION
We want to find the inverse of the exponential function,
[tex]y = {12}^{x} [/tex]
The above function is an exponential function, so we expect the inverse to be a logarithmic function.
We now interchange x and y.
[tex]x = {12}^{y} [/tex]
We now make y the subject by taking antilogarithm of both sides to obtain,
[tex]y = log_{12}(x) [/tex]
This last function is the inverse of
.
[tex]y = 12^x[/tex]
Hence the correct answer is D
The inverse of the function [tex]\rm log_{12}y = x[/tex] is [tex]y= log_{12} \dfrac{1}{x}[/tex].
Given to us
[tex]y = 12^x[/tex]
The inverse of a function y which is dependent on x, we solve the function such that the function becomes independent of x and depends on y.
What is the inverse of the function [tex]\rm log_{12}y = x[/tex]?
We know that to write the inverse of a function y which is dependent on x, we solve the function such that the function becomes independent of x and depends on y.
[tex]y = 12^x[/tex]
Taking antilog,
[tex]\rm log_{12}y = x[/tex]
Substitute the values,
[tex]y= log_{12} \dfrac{1}{x}[/tex]
Hence, the inverse of the function is [tex]y= log_{12} \dfrac{1}{x}[/tex].
Learn more about the Inverse function:
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