so hmmm bear in mind that, 9months from 12 months in a year, is 9/12 years, or 3/4
[tex]\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad
\begin{cases}
A=\textit{accumulated amount}\to &\$2700\\
P=\textit{original amount deposited}\\
r=rate\to 11\%\to \frac{11}{100}\to &0.11\\
t=years\to \frac{9}{12}\to &\frac{3}{4}
\end{cases}
\\\\\\
2700=P\left(1+0.11\cdot \frac{3}{4} \right)[/tex]
solve for P
