Question

According to the general equation for conditional probability, if P(A upside down u B)= 5/7 and P(B)=7/8 , what is P(A|B)?

Answer 1

$P(A | B) = \frac{P(A \cap B)}{P(B)}$


$P(A|B) = \frac{5/7}{7/8}$


$P(A|B) = \frac{5}{7} \div \frac{7}{8}$


$P(A|B) = \frac{5}{7}\times\frac{8}{7}$


$P(A|B) = \frac{5*8}{7*7}$


$P(A|B) = \frac{40}{49}$

Answer 2

The value of the conditional probability  P(A |B) is 5/8

How to determine the conditional probability?

The given parameters are:

P(A n B)= 5/7 and P(B)=7/8

The value of P(A|B) is calculated using:

P(A |B) = P(A n B)/P(B)

So, we have:

P(A |B) = 5/7 / 7/8

Evaluate

P(A |B) = 5/8

Hence, the value of the conditional probability  P(A |B) is 5/8

Read more about probability at:

https://brainly.com/question/25870256

#SPJ2