Question

Solve for the zeros of the quadratic function f(x) = 9x2 + 6x + 1. Write the answer as a fraction.

Answer 1

x=-b+√b²-4ac/2a

x=-6+ √(-6)²-4(9)(1)/2(9)

x=-6+ √36-36/18

"x=-1/3 is correct answer."

Hope this helps!

Thanks!

-Charlie

Answer 2

The zeros of the quadratic function f(x) = 9x2 + 6x + 1 is determined as -1/3.

Zero of the quadratic equation

The zeros of the quadratic equation is determined as follows;

9x² + 6x + 1 = 0

expand the equation;

9x² + 3x + 3x + 1 = 0

3x(3x + 1) + 1(3x + 1) = 0

(3x + 1)(3x + 1) = 0

3x + 1 = 0  or 3x + 1 = 0

3x = -1

x = -1/3 twice

Thus, the zeros of the quadratic function f(x) = 9x2 + 6x + 1 is -1/3.

Learn more about zeros of function here: https://brainly.com/question/446160