Question

Which equations have a leading coefficient of 3 and a constant term of –2? Check all that apply.
0 = 3x2 + 2x – 2
0 = –2 – 3x2 + 3
0 = –3x + 3x2 – 2
0 = 3x2 + x + 2
0 = –1x – 2 + 3x2

Answer 1

Answers are: choice A, choice C, choice E

Explanation: The leading coefficient is the number that is to the left of the term with the largest exponent, which in this case is 2. The term 3x^2 is the leading term with the coefficient of 3. This is why the leading coefficient is 3 for choice A, choice C, and choice E. Choice B has a leading coefficient of -3 so we can rule that out. Choice D has a leading coefficient of 3, but the constant term is NOT -2. Instead the constant term is +2, so we can rule out choice D as well. The other choices that haven't been eliminated all have 3x^2 somewhere in them, as well as the constant term -2. The other x term isn't relevant to the restrictions placed in the instructions. 

Answer 2

Equation 1, equation 3 and equation 5 has the leading coefficient of 3 and a constant term of –2.

How do you find out the leading coefficient and constant term?

In the given equations, the variables written in front of the largest exponent of the equation are called Leading Coefficients.

For equation 1 is $3x^2 +2x-2=0$, the leading coefficient is 3 and it also has the constant term -2.

For equation 2 that is $-3x^2 +3-2=0$, the leading coefficient is -3 and it also has the constant term -2.

For equation 3 that is $3x^2 -3x-2=0$, the leading coefficient is 3 and it also has the constant term -2.

For equation 4 that is $3x^2 +x+2=0$, the leading coefficient is 3 and it also has the constant term 2.

For equation 5 that is $3x^2 -x-2=0$, the leading coefficient is 3 and it also has the constant term -2.

Hence, equation 1, equation 3 and equation 5 have the leading coefficient of 3 and a constant term of –2.

For more details about the leading coefficient, follow the link given below.

https://brainly.com/question/9338204.