Question

For two consecutive integers, the sum of the smaller and twice the larger is 29. find the smaller integer.

Answer 1

x and x + 1 are the integers

x + 2*(x+1) = 29

x + 2x + 2 = 29

3x = 27

x = 9

The integers are 9 and 10

Answer 2

Consecutive numbers are numbers that have a difference of 1

The smaller number is 9

Let the consecutive numbers be x and y, such that:

y = x + 1

From the question, we have:

x + 2y = 29

Substitute y = x + 1

x + 2(x + 1) = 29

Open brackets

x + 2x + 2 = 29

3x + 2 = 29

Subtract 2 from both sides

3x = 27

Divide both sides by 3

x = 9

Hence, the smaller number is 9

Read more about consecutive numbers at:

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