well, for a line with a slope of 3/4, any other parallel line to it, will also have the same slope of 3/4
so if the line through (2, -1) is parallel to it, it has a slope of 3/4 as well
[tex]\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ 2}}\quad ,&{{ -1}})\quad
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{3}{4}
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\qquad
\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=-1\\
x_1=2\\
m=\frac{3}{4}
\end{cases}\\
\textit{and move everything}\\
\textit{to the left-hand-side}
\end{array}\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}[/tex]
