Question

What are the solutions of x2 + 10x + 16 = 0?
1.Write the equation in standard form.
2.Factor the polynomial.
3.Apply the zero product property.
4.Solve the resulting equations
x2 + 10x + 16 = 0

(x + 2)(x + 8) = 0

x + 2 = 0 or x + 8 = 0

x = and x=

Answer 1

Answer:

x= -2 and x= -8

Step-by-step explanation:

Given: $x^2+10x+16=0$

Solution:

1) equation in standard form is  $ax^2+bx+c=0$

therefore, $x^2+10x+16=0$ is in standard form.

2) factors of the polynomial of the given equation is :

$(x+2)(x+8)$

3) zero product property sate that if a.b=0 then either a=0 or b=0

applying this property,

  $(x+2)(x+8)=0$

⇒either (x+2)=0 or (x+8)=0

⇒either x= -2 or x= -8

4) solving the equation we get, x= -2 and x= -8

Answer 2

The factor of the equation x² + 10x + 16 = 0 is (x + 2 )(x + 8). The value of x is -8 and -2.

What is the Quadratic equation?

It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation. The general form of the quadratic equation is ax² + bx + c.

Given

A quadratic equation is x² + 10x + 16 = 0

How to find the value of x?

A quadratic equation will be

x² + 10x + 16 = 0

By factorisation method

x² + 8x + 2x + 16 = 0

      (x + 8)(x + 2) = 0

                        x = -8 and -2

So the value of x is -8 and -2.

More about the quadratic equation link is given below.

https://brainly.com/question/17177510