Respuesta :
Answer:
C) 4.88 hr; D) convenience; B) P(A and B); A) 72; B) mean = 27.5, range = 20; no function shown to answer the question; A) 6.58, 0.42; D) average class size, cost; D) 7.8
Step-by-step explanation:
#1) To find the mean, we add all of the numbers and divide by the number of data values:
(1.7+7.7+8.3+1.6+5.1)/5 = 24.4/5 = 1.88
#2) This is a convenience sample because it was easy for the analyst to do; she did not use random sampling or any sort of groups, and she did not choose every kth item.
#3) The probability of two events is P(A and B) by definition.
#4) To find the total number of choices, we multiply the number of flavors by the number of toppings:
6(12) = 72
#5) To find the mean, add all of the data values up and divide by the number of data values:
(26+19+23+39+31+34+23+25)/8 = 220/8 = 27.5
To find the range, subtract the highest and lowest values:
39-19 = 20
#6) There is no function given to answer the question.
#7) Using the quadratic formula,
[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\=\frac{--28\pm \sqrt{(-28)^2-4(4)(11)}}{2(4)}\\\\=\frac{28\pm \sqrt{784-176}}{8}\\\\=\frac{28\pm \sqrt{608}}{8}\\\\=\frac{28\pm 24.65766}{8}\\\\=\frac{28+24.65766}{8},\frac{28-24.65766}{8}\\\\=\frac{52.65766}{8},\frac{3.34234}{8}\\\\=6.58,0.42[/tex]
#8) The independent quantity is the one that causes the dependent to change. In this case, the average class size causes the cost of books to change; this means the average class size is independent and the cost of books is dependent.
#9) Using the distance formula,
[tex]d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\=\sqrt{(8-2)^2+(3-8)^2}\\\\=\sqrt{6^2+(-5)^2}\\\\=\sqrt{36+25}=\sqrt{61}=7.8[/tex]