Respuesta :
Step [tex] 1 [/tex]
Find the volume of a cylinder
we know that
volume of a cylinder is equal to
[tex] V1=\pi r^{2} h [/tex]
in this problem
[tex] r=8\ units \\ h=15\ units [/tex]
Substitute
[tex] V1=\pi 8^{2} 15 [/tex]
[tex] V1=960\pi\ units^{3} [/tex]
Step [tex] 2 [/tex]
Find the volume of a cone
we know that
volume of a cone is equal to
[tex] V2=\frac{1}{3}\pi r^{2} h [/tex]
in this problem
[tex] r=8\ units \\ l=17\ units \\ h=? [/tex]
applying the Pythagorean Theorem find the value of h
[tex] h^{2} =l^{2}-r^{2}\\ h^{2} =17^{2}-8^{2}\\ h^{2}=225\\ h=15\ units [/tex]
[tex] V2=\frac{1}{3}\pi 8^{2} 15\\ \\ V2=320\pi \ units^{3} [/tex]
Step [tex] 3 [/tex]
Find the unfilled volume inside the cylinder
[tex] V1-V2=960\pi -320\pi =640\pi \ units^{3} [/tex]
therefore
the answer is
the unfilled volume inside the cylinder is equal to [tex] 640\pi \ units^{3} [/tex]
The unfilled volume inside the cylinder is 640π unit³
Volume
Volume shows the amount of space enclosed by a closed surface. It is the amount of space that an object occupies, or that is enclosed within a container.
The volume of a cylinder = πr²h
where r is the radius, h is the height.
r = 8., h = 15 feet, hence:
Volume = π(8)²(15) = 960π unit³
For the cone where l is the slant, h is the height.
The volume of a cone = [tex]\frac{1}{3}\pi r^2\sqrt{l^2*r^2}= \frac{1}{3}\pi (8)^2\sqrt{17^2*8^2}=320\pi \ unit^3[/tex]
Unfilled volume = 960π - 320 π = 640π unit³
The unfilled volume inside the cylinder is 640π unit³
Find out more on volume at: https://brainly.com/question/12410983