x the 1st table
y the second
z the third
The equation is : x+y+z =16.9
But we know (given) that x=2y & z=(1/3)y
Calculate everything in term of x:
x= 2y==> x/2 =y
z=(1/3)y ==> & since y=x/2 then z= (1/3)(x/2)==> z=x/6; y=5.07 & z =1.69
x + x/2 + x/6 = 16.9===>1.666x = 16.9===> x= 10.14