Respuesta :
Answer in one complete sentence:
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"The length of the frame is ten (10) inches."
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Explanation:
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Perimeter = P = 36 in.
Length = L = 2 +2
Width = w .
_____________________________________________
These are the two equations for the system of equations:
P = 2L + 2w = 36 in.
L = 2 + w
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Solve for "L" (length) of the frame.
______________________________________
In the equation:
______________________________________
P = 2L + 2w = 36.
{Note: standard knowledge; and/or look up:
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Formula for the Perimeter of a rectangle: P = 2L + 2w} ;
_______________________________________
We are given: P = 36 in.
Rewrite, substituting "2+w" for "L" ;
P = 2(2+w) + 2w = 36 ;
___________________________
Note: 2(2+w) = 2*2 + 2w = 4 + 2w .
Now, Rewrite the equation, substituting "(4 + 2w) for "2(2+w)" ;
__________________________________________________
P = (4 + 2w) + 2w = 36 ;
P = 4 + 2w + 2w = 36 ;
Combine the "like terms" ;
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+ 2w + 2w = 4w ;
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P = 4 + 4w = 36 ;
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↔ 4 + 4w = 36 ;
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Subtract "4" from EACH SIDE of the equation:
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→ 4 + 4w − 4 = 36 − 4 ;
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to get:
____________________________________________
→ 4w = 32 ;
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→ Divide EACH SIDE of the equation by "4" ; to isolate "w" on one side of the equation; and to solve for "w" ;
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→ 4w / 4 = 32 / 4 ;
→ w = 8 .
____________________________________________
Now, to solve for: "L" (the length).
____________________________________________
Length: L = 2 + w ;
→ L = 2 + 8 = 10 inches.
____________________________________________
Answer in one complete sentence:
____________________________________________
"The length of the frame is ten (10) inches."
____________________________________________
____________________________________________
"The length of the frame is ten (10) inches."
_____________________________________________
Explanation:
_____________________________________________
Perimeter = P = 36 in.
Length = L = 2 +2
Width = w .
_____________________________________________
These are the two equations for the system of equations:
P = 2L + 2w = 36 in.
L = 2 + w
_____________________________________________
Solve for "L" (length) of the frame.
______________________________________
In the equation:
______________________________________
P = 2L + 2w = 36.
{Note: standard knowledge; and/or look up:
______________________________________
Formula for the Perimeter of a rectangle: P = 2L + 2w} ;
_______________________________________
We are given: P = 36 in.
Rewrite, substituting "2+w" for "L" ;
P = 2(2+w) + 2w = 36 ;
___________________________
Note: 2(2+w) = 2*2 + 2w = 4 + 2w .
Now, Rewrite the equation, substituting "(4 + 2w) for "2(2+w)" ;
__________________________________________________
P = (4 + 2w) + 2w = 36 ;
P = 4 + 2w + 2w = 36 ;
Combine the "like terms" ;
____________________________________________
+ 2w + 2w = 4w ;
____________________________________________
P = 4 + 4w = 36 ;
____________________________________________
↔ 4 + 4w = 36 ;
____________________________________________
Subtract "4" from EACH SIDE of the equation:
____________________________________________
→ 4 + 4w − 4 = 36 − 4 ;
____________________________________________
to get:
____________________________________________
→ 4w = 32 ;
____________________________________________
→ Divide EACH SIDE of the equation by "4" ; to isolate "w" on one side of the equation; and to solve for "w" ;
____________________________________________
→ 4w / 4 = 32 / 4 ;
→ w = 8 .
____________________________________________
Now, to solve for: "L" (the length).
____________________________________________
Length: L = 2 + w ;
→ L = 2 + 8 = 10 inches.
____________________________________________
Answer in one complete sentence:
____________________________________________
"The length of the frame is ten (10) inches."
____________________________________________