Respuesta :

tonb
Imagine an xy system on top of the origin of the circle. Then the y coordinate of B is 3-2.25 = 0.75.

Suppose there is a line from the center to B. Line OA has an angle alpha with the x axis. Simple trigonometry tells us that 3*sin(alpha) = 0.75.

And it also tells us that line AB would be 2*3*cos(alpha).

So AB = 6*cos( arcsin(0.75/3) ) ≈ 5.8

Thank god that is in the list as answer C!!

Answer:

The answer is the option C

[tex]5.8\ ft[/tex]

Step-by-step explanation:

see the attached figure with letters to better understand the problem

we know that

In the right triangle ACD

Applying the Pythagoras Theorem

[tex]AC^{2} =CD^{2}+AD^{2}[/tex]

Solve for AD

[tex]AD^{2}=AC^{2}-CD^{2}[/tex]

in this problem we have

[tex]AC=r=3\ ft[/tex]

[tex]CD=3-2.25=0.75\ ft[/tex]

substitute

[tex]AD^{2}=3^{2}-0.75^{2}[/tex]

[tex]AD=2.90\ ft[/tex]

[tex]AB=2AD[/tex]

[tex]AB=2(2.90)=5.80\ ft[/tex]

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