The equation given is: [tex] \frac{6}{ a^{2} - 7a+6 }[/tex].
The second equation will have x as the unknown equivalent numerator with the denominator as (a-6)(a-1)(a+6).
Simplifying the second equation would result to:
[tex] \frac{x}{(a-6)(a-1)(a+6)} = [tex]\frac{6}{ a^{2} - 7a+6 } [/tex]
Equating the two equations:
[tex]\frac{6}{ a^{2} - 7a+6 } = \frac{x}{ (a^{2} - 7a+6) (a+6) }
[/tex]
x = 6(a+6). The numerator of the equivalent equation is 6(a+6).
