Question

The piecewise function f(x) is defined below. What is the value of f(1)? mc012-1.jpg f(1) = –2 f(1) = –1 f(1) = 2 f(1) = 3

Answer 1

Given the piecewise function f(x) is defined below
 $f(x)= \left \{ {{x^2+1; \ \ \ -4 \leq x \ \textless \ 1} \atop {-x^2; \ \ \ 1 \leq x\ \textless \ 2}} \atop {3x; \ \ \ x \geq 2} \right.$

In the piecewise function, we use the top function, when x has a value from -4 to 1, 1 not included. We use the middle function when x has a value from 1 to 2, 2 not included. And we use the bottom function when x has a value of 2 and above.

Therefore, to find f(1), we make use of the middle function.
$f(1) = -(1)^2=-1$

Answer 2

The value f(1) is -1, the correct option is B.

Piecewise function

The piecewise function is defined as by the multiple sub-functions in the different domains.

Given information

The piecewise function f(x) is defined as;

$\rm f(x)=x^2+1; \ -4\leq x<1\\\\f(x)=-x^2 ; \ 1\leq x<2\\\\f(x)=3x; \ x\geq 2$

The value of the piecewise function is defined as the sub-functions for the domain of the second function.

The value of (1) is;

$\rm f(1)=-(1)^2\\\\f(1)=-1$

Hence, the value f(1) is -1.

To know more about piecewise functions click the link given below.

https://brainly.com/question/17966003