We see that this function has a horizontal asymptote that crosses the y-axis at 2. This means that we can eliminate choices A and C.
From there, we can plug in values for points on the graph into the equation to see if they are true.
f(x)=6(1/3)^x+2
f(1)=6(1/3)^1+2
f(1)=2+2
=4 (Gives us the other coordinate)
f(x)=4(1/3)^x+2
f(1)=4(1/3)^1+2
=(4/3)+2
=3.33 (Does not give us the other coordinate)
Our correct answer choice is B
:)