Given that 8% of the students are Swedish, this means that 100 - 8 = 92% are not Swedish.
Let S represent the event that a student is Swedish and N represent the event that a student is not a Swedish.
Then, the probability that a student chosen at random is a Swedish, P(S), = 8% = 0.08
The probability that a student chosen at random is not a Swedish, P(N), = 92% = 0.92
That the first Swedish person found was on the third trial means that the first and second trial produced a non-Swedish.
Therefore, the required probability = 0.92 x 0.92 x 0.08 = 0.068 to three decimal places.