Respuesta :
This parabola y=f(x) = (x²-6x+8) is:
1) Open downward (a>0)
2) it's axis of symmetry = -b/2a = 62 = 3
3) for x=3 , y= -1, So its minimum is at (3,-1)
4) Since its minimum is at y=-1, so it cannot go below -1
5) So its range is {y∈R: y>= - 1}
or all real numbers greater than or equal to −1
1) Open downward (a>0)
2) it's axis of symmetry = -b/2a = 62 = 3
3) for x=3 , y= -1, So its minimum is at (3,-1)
4) Since its minimum is at y=-1, so it cannot go below -1
5) So its range is {y∈R: y>= - 1}
or all real numbers greater than or equal to −1