Question

Which volume of 0.600 M H2SO4(aq) exactly neutralizes 100. milliliters of 0.300 M Ba(OH)2(aq)?

Answer 1

Answer: 50 ml of 0.600 M of sulfuric acid will exactly neutralize the 100 ml of 0.300 M of barium hydroxide solution.

Explanation:

$H_2SO_4+Ba(OH)_2\rightarrow BaSO_4+2H_2O$

According to reaction 1 mole sulfuric acid neutralizes 1 mole oh barium hydroxide.

$M_1=0.600 M,H_2SO_4$

$V_1=?$

$M_2=0.300 M,Ba(OH)_2$

$V_2=100 ml$

$M_1V_1=M_2V_2$

$V_1=\frac{M_2\times V_2}{M_1}=50 ml$

50 ml of 0.600 M of sulfuric acid will exactly neutralize the 100 ml of 0.300 M of barium hydroxide solution.

Answer 2

The volume of 0.600 M sulfuric acid exactly neutralizes 100 milliliters of 0.300 M barium hydroxide is 50 ml.

What is volume?

Volume is the total space occupied by a three-dimensional object. It is a scalar quantity.

The reaction is $\rm H_2SO_4 + Ba(OH)_2 \rightarrow BaSO_4 + H_2O$

By the formula of $\rm M_1V_1 = M_2V_2$, this formula is used to calculate dilution.

Given, that M1 = 0.600

M2 = 0.300

V2 = 100

V1 is to find

Now, placing the values in the equation of dilution

$\rm V_1 = \dfrac{M_2V_2}{M_1} \\\\\\ V_1 = \dfrac{0.300 \times 100\;ml}{0.600} = 50\;ml$

Thus, the volume is 50 ml.

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