Question

$(x^2+16x)^2=17^2$

I know the answers. Please show me the correct way to solve this.

Answer 1

(x² + 16x)² = 17²

√x² + 16x)²  =  √17²
(x²  +  16x)   = (+-)17
1st equation: x²+16x-17 = 0
2nd equation:x²+16x+17 =0
Let's solve these 2 quadratic equation:
1st equation x' =1 & x" = - 17
2nd equation x'= (-8+√47) & x" =(-8-√47)