Question

PLEASE HELP! WILL GIVE BRAINLIEST ANSWER!!!
A box contains 8 white cards and 6 black cards.

What is the probability of choosing a black card then a white card, without replacement?


12/49

24/91

16/49

15/91

Answer 1

A --  "a black card was selected, followed by a white card"

1)

6 + 8 = 14

$P(A)=\frac{6}{14}*\frac{8}{14-1}=\frac{3}{7}*\frac{8}{13}=\frac{24}{91}$

2) 

$n(S)=14*13=182$  Possible events

$n(A)=6*8=48\\\\ P(A)=\frac{n(A)}{n(S)}=\frac{48}{182}=\frac{24}{91}$