friedalafiesta
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PLEASE HELP! Probability!
A spinner is divided into four equal sections that are numbered 2, 3, 5, and 8. The spinner is spun twice.

How many outcomes have a sum greater than 7 and contain at least one even number?

Respuesta :

MathGenius777
2+3=5 no
2+5=7 no
2+8=10 yes (if zero counts as an even number)
5+3=8 yes
5+8=13 no
8+3=11
So 2/6 = 1/3 1/3 should be the answer
fichoh

Using the principle of probability, the probability of having a sum greater than 7 with atleast one even number is 7/16

Sample space :

____ 2_____ 3 ____ 5 ____ 8

|

2__2,2 ____2,3___ 2,5____2,8

3__2,3_____3,3___5,3____3,8

5 _ 2,5 ____ 3,5 __ 5,5 ___ 5,8

8 _ 2,8 ____3,8 ___5,8____8,8

Sum greater than 8 = (2,8),(3,8),(5,5),(5,8),(2,8),(3,8),(5,8),(8,8)

Greater than 8 and contains atleast an even number :

  • (2,8), (3,8), (5,8),(2,8),(3,8),(5,8),(8,8) = 7

Recall ::

  • Probability = required outcome / Total possible outcomes

Hence,

  • Probability = required outcome / sample space

  • 7/16

Therefore, the required probability is 7/16

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